Tab Lice
Transcript of Tab Lice
Adicione formule
sin2 x+ cos2 x = 1 tgx · ctgx = 1 sin(x± y) = sinxcosy± cosxsiny
tg(x± y) =tgx± tgy
1∓ tgx · tgycos(x± y) = cosxcosy∓ sinxsiny ctg(x± y) =
ctgx · ctgy∓1ctgy± ctgx
sinx = 2sinx2
cosx2
cosx = cos2 x2− sin2 x
2tgx =
2tg x2
1− tg2 x2
ctgx =ctg2 x
2 −12ctg x
2sin2 x =
1− cos(2x)2
cos2 x =1+ cos(2x)
2
tg2 x =1− cos(2x)1+ cos(2x)
ctg2 x =1+ cos(2x)1− cos(2x)
sinx+ siny = 2sinx+ y
2cos
x− y2
sinx− siny = 2cosx+ y
2sin
x− y2
cosx+ cosy = 2cosx+ y
2cos
x− y2
cosx− cosy =−2sinx+ y
2sin
x− y2
Nizovi i limesi nizova
Aritmeticki i geometrijski niz
Za aritmeticki niz an = a1 +(n−1)d, n ∈ N važin
∑k=1
ak =n2(a1 +an) = na1 +
n(n−1)2
d.
Za geometrijski niz bn = b1qn−1, n ∈ N važin
∑k=1
bn =
b11−qn
1−q , q = 1
nb1 , q = 1
∞
∑k=1
bn =
b11
1−q , |q| ≤ 1
divergira , |q| ≥ 1
Tablica limesa nizova
limn→∞
qn =
0 , |q|< 1
1 , q = 1
∞ , q > 1
divergira , q ≤−1
. limn→∞
1nα =
0 , α > 0
1 , α = 1
∞ , α < 0
. limn→∞
nα =
0 , α < 0
1 , α = 1
∞ , α > 0
.
limn→∞
nbqn = 0; |q|< 1, b ∈ R. limn→∞
n√
a = 1; a > 0. limn→∞
n√
n = 1.
limn→∞
nα
n!= 0; α ∈ R. lim
n→∞
an
n!= 0; a ∈ R. lim
n→∞
(1+
1n
)n= e.
limn→∞
an =±∞ ⇒ limn→∞
(1+
1an
)an
= e.
Tablica limesa funkcija
limx→±∞
pnxn + pn−1xn−1 + . . .+ p1x+ p0
qmxm +qm−1xm−1 + . . .+q1x+q0=
0 , n < m
pnqn
, n = m
±∞ , n > m
. limx→±∞
(1+
1x
)x= e. lim
x→0(1+ x)
1x = e.
limx→∞
xα =
0 , α < 0
1 , α = 0
∞ , α > 0
limx→∞
1xα =
0 , α > 0
1 , α = 0
∞ , α < 0
. limx→0
sinxx
= 1.
limx→0
ex −1x
= 1. limx→0
ln(1+ x)x
= 1. limx→0
(1+ x)α −1x
= α; α ∈ R.
Tablica izvoda funkcija
f (x) = α 7→ f ′ (x) = 0, α ∈ R. f (x) = xα 7→ f ′ (x) = αxα−1, α ∈ R. f (x) = ex 7→ f ′ (x) = ex.
f (x) = ax 7→ f ′ (x) = lna ·ax, a > 0. f (x) = lnx 7→ f ′ (x) =1x
. f (x) = loga x 7→ f ′ (x) =1
lna · x, a > 0.
f (x) = sinx 7→ f ′ (x) = cosx. f (x) = cosx 7→ f ′ (x) =−sinx. f (x) = tgx 7→ f ′ (x) =1
cos2 x.
f (x) = cosx 7→ f ′ (x) =−sinx. f (x) = arcsinx 7→ f ′ (x) =1√
1− x2. f (x) = arccosx 7→ f ′ (x) =− 1√
1− x2.
f (x) = arctgx 7→ f ′ (x) =1
1+ x2 . f (x) = arcctgx 7→ f ′ (x) =− 11+ x2 .
Tablica razvoja funkcija u Maklorenov red
ex =∞
∑n=0
xn
n!, x ∈ R. sinx =
∞
∑n=0
(−1)n x2n+1
(2n+1)!, x ∈ R. cosx =
∞
∑n=0
(−1)n x2n
(2n)!, x ∈ R.
ln(1+ x) =∞
∑n=1
(−1)n−1 xn
n, x ∈ (−1,1]. ln(1− x) =−
∞
∑n=1
xn
n, x ∈ [−1,1). (1+ x)m =
m
∑n=0
(mn
)xn, x ∈ R, m ∈ N.
(1+ x)m =∞
∑n=1
(mn
)xn, x ∈ (−1,1), m ∈ N.
11− x
=∞
∑n=0
xn, x ∈ (−1,1).
gde je za m ∈ N i n ∈ N,(m
0
)= 1,
(mn
)=
m(m−1)(m−2) . . .(m−n+1)n!
Tablica integrala
0 ·dx = c.∫
dx = x+ c.
∫xαdx =
xα+1
α+1+ c, α ∈ R\{−1}.
∫ 1x
dx = ln |x|+ c.
∫exdx = ex + c.
∫axdx =
ax
lna+ c, a > 0, a = 1.
∫sinxdx =−cosx+ c.
∫cosxdx = sinx+ c.
∫tgxdx =− ln |cosx|+ c.
∫ctgxdx = ln |sinx|+ c.
∫ 1cos2 x
dx = tgx+ c.∫ 1
sin2 xdx =−ctgx+ c.
∫shxdx = chx+ c.
∫chxdx = shx+ c.
∫thxdx = ln |chx|+ c.
∫cthxdx = ln |shx|+ c.
∫ 1ch2 x
dx = thx+ c.∫ 1
sh2 xdx =−cthx+ c.
∫ 1a2 + x2 dx =
1a
arctgxa+ c, a = 0.
∫ 1a2 − x2 dx =
12a
ln∣∣∣∣a+ xa− x
∣∣∣∣+ c =1a
arcthxa+ c, a = 0.
∫ 1√x2 +a2
dx = ln∣∣∣x+√
x2 +a2∣∣∣+ c = arsh
xa
, a = 0.∫ 1√
x2 −a2dx = ln
∣∣∣x+√x2 −a2
∣∣∣+ c = archxa
, a = 0.
∫ 1√a2 − x2
dx = arcsinxa+ c, a = 0.