REPRESENTATIONS OF CRYSTALLOGRAPHIC GROUPS I....
Transcript of REPRESENTATIONS OF CRYSTALLOGRAPHIC GROUPS I....
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REPRESENTATIONS OF CRYSTALLOGRAPHIC
GROUPS I.
GENERAL INTRODUCTION
Bilbao Crystallographic Server
http://www.cryst.ehu.es
Cesar Capillas, UPV/EHU 1
Mois I. AroyoUniversidad del Pais Vasco, Bilbao, Spain
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Homomorphism and Isomorphism
G G’. .. ..
G={g} G’={g’}Φ(g)=g’
Φ: G G’
Φ(g1)Φ(g2)= Φ(g1 g2)homomorphic condition
Example: 4mm
{1,-1}
{1, 4, 2, 4-1, mx, my, m+, m-}
{1,-1} ?miércoles 24 de junio de 2009
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Isomorphism
G G’
. .. ..G={g} G’={g’}
Ψ(g)=g’
Ψ: G G’
Ψ(g1) Ψ(g2)= Ψ(g1 g2)
Example: 4mm {1, 4, 2, 4-1, mx, my, m+, m-}
?
.
Ψ-1(g’)=g
422 {1, 4, 2, 4-1, 2x, 2y, 2+, 2-}miércoles 24 de junio de 2009
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Representations of Groups
group G {e, g2, g3, ..., gi,... ,gn}
D(G): rep of G {D(e), D(g2), D(g3),..., D(gi),... ,D(gn)}
Φ
D(gj): nxn matrices detD(gj)≠0
D(gi)D(gj)=D(gigj)
Example: trivial (identity) representation
faithful representation
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Two-dimensional faithful representation of 4mm
{1, 4, 2, 4-1, mx, my, m+, m-}
001
1
0
0-1
110
0-1
Determine the rest of the matrices
?
EXERCISES
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Representations of Groups
equivalent representations
D1(G)={D1(gi), gi∈G}reps of G: D2(G)={D2(gi), gi∈G}dim D1(G)= dim D2(G)
D1(G) ∼ D2(G) if D1(G) = S-1D2(G)S∃ S:
reducible and irreducible
if D(G) ∼ D’(G) =D(G)reducible
Di(G)reps of G
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Representations of GroupsBasic results
Schur lemma I
D1(G)={D1(gi), gi∈G}irreps of G: D2(G)={D2(gi), gi∈G}
dim D1(G)=dim D2(G), D1(G) ∼ D2(G)
D1(G)A = A D2(G)if ∃ A:then A=0{ det A≠0
Schur lemma IID1(G)={D1(gi), gi∈G}irrep of G:
D1(G)B = B D1(G)if ∃ B:
D1(G)A = A D2(G)
then B=cI
irreps of abelian groups one-dimensional
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Representations of GroupsBasic results
number and dimensions of irreps
number of irreps = number of conjugacy classesorder of G =∑[dimDi(G)]2
great orthogonality theorem
D1(G), D2(G), irreps of G:
∑ D1(g)jk* D2(g)st =|G|d
δ12δjsδkt
g
dim D1(G)=d
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Representations of Groups
exampleirreps of 222
abelian group(2i)2=(2i 2j)2=1[D(2i)]2=D[(2i 2j)]2=D(1)=1
D(2i)=∓1
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Characters of RepresentationsBasic results
characterproperties
η(g) = trace[D(g)]=∑ D(g)ii
D1(G) ∼ D2(G) η1(g)= η2(g), g∈G
g1 ∼ g2 η1(g)= η2(g), g∈G
orthogonality
∑ η1(g)* η2(g) =|G|
δ12
g
1
∑ ηp(Cj)* ηp(Ck) =|G|
δjk
p
1|Cj|
rows
columns
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example: 422
Characters of Representations
∑ η1(g)* η2(g) =|G|
δ12
g
1
rows
∑ ηp(Cj)* ηp(Ck) =|G|
δjk
p
1|Cj|
columns
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Characters of Representations
reducible rep m1D1(G)⊕m2D2(G)⊕...⊕mkDk(G)
∑ ηi(g)*η(g)=|G|
mig
1
magic formula
irreducibilitycriteria
∑ |η(g)|2 =|G| g1 1
miDi(G)D(G)~
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!p(gk) = exp(2!ik)p ! 1
ng
n= e p = 1, ..., n
Representations of cyclic groups
G = !g" = {g, g2, ...gk, ...}
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Direct-product groups and their representations of
Direct-product groups
G1 x G2 = {(g1,g2), g1∈G1, g2∈G2} (g1,g2) (g’1,g’2)= (g1g’1, g2g’2)
G1 x {1,1} group of inversion
Irreps of direct-product groups
D1 x D2
G1 x G2G1 G2
D1 D2
{D1(e) x D2(e) D1(gi) x D2(gi),..., ,...}
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+ +
+ -
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Direct product of representations
D1(G): irrep of G{D1(e), D1(g2),... ,D1(gn)}
D2(G): irrep of G{D2(e), D2(g2),... ,D2(gn)}
Reduction
irreps of G
miDi(G)
D1 x D2D1 x D2
D1 x D2 {D1(e) x D2(e) D1(gi) x D2(gi),..., ,...}=
Direct-product representation
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Direct-product (Kronecker) product of matrices
=
(A x B)ik,jl =AijBkl η( )(gi)= ηA(gi) ηB(gi)A x B
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EXERCISES Problem 1
D1 x D2 {D1(e) x D2(e) D1(gi) x D2(gi),..., ,...}=
Direct-product representation
∑ ηi(g)*η(g)2 =|G|
mig
1
miDi(G)D1 x D2~
Decompose the direct product representation ExE into irreps of 4mm
η( )(gi)= η(gi) η(gi)D1 x D2
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Subduction
SUBDUCED REPRESENTATION
group G{e, g2, g3, ..., gi,... ,gn}
subgroup H<G{e, h2, h3, ...,hm}
D(G): irrep of G{D(e), D(g2), D(g3),..., D(gi),... ,D(gn)}
subduced rep of H<G{D(e), D(h2), D(h3), ...,D(hm)}
irreps of H
{D(G) H}:
{D(G) H}S-1{D(G) H}S
miDi(H)
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SUBDUCED REPRESENTATION
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EXERCISES Problem 1
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EXERCISES Problem 1
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Conjugate representations
H= {e, h2, h3, ..., hi,... ,hn}
{D(e), D(h2),... ,D(hn)}
conjugate representation
∆
G H: DS(H)={DS(g-1hig), hi∈H, g∈G,g∉H}
{D(g-1eg), D(g-1h2g), ... ,D(g-1hng)}conjugated irrep
{D(e), D(h’2),... ,D(h’n)}DS(H)=
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Conjugate representations
properties
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Conjugate representations and orbits
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EXERCISES Problem 2.
(i) Consider the irreps of the group 4 and distribute them into orbits with respect to the group 422
(ii) Consider the irreps of the group 222 and distribute them into orbits with respect to the group 422
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Problem 2(i).SOLUTION
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SOLUTION Problem 2(i).
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Problem 2(ii).SOLUTION
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Problem 2(ii).SOLUTION
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INDUCED REPRESENTATION
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INDUCED REPRESENTATION
Induction matrix M(g)monomial matrix
1 0 00
00
000
1
1
1......
......
... 0
...
...
...gr
g2
g1
g1 g2 gr
M(g)mn= 1 if gm-1ggn=h0 if gm-1ggn∉H{
Induced representation DInd(g)super-monomial matrix
g1 g2 ... gr
g1
g2 ...
...gr ...
DJ(h) 0
0
0 000 0
DJ(h)
DJ(h)
DJ(h) 00 0... ...
...
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EXERCISES Problem 3.
Determine representations of 4mm induced from the irreps of {1,my}.
Notation:my=mxz
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Decompostion of 4mm with respect to the subgroup {1,mxz}
Step 1.
Step 2. Construction of the induction matrix
M(g)mn= 1 if gm-1ggn=h0 if gm-1ggn∉H{
Hint to Problem 3.
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Determine representations of 4mm induced from the irreps of m
Example:
Decompostion of 4mm with respect to the subgroup {1,mxz}
Step 1.
4mm= {1,mxz}∪myz {1,mxz}∪4z {1,mxz}∪mx-x {1,mxz}
coset representatives {1, myz,4z,mx-x}
SOLUTION Problem 3.
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Step 2. Construction of the induction matrix
M(g)mn= 1 if gm-1ggn=h0 if gm-1ggn∉H{
SOLUTION Problem 3.
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The inductionmatrix for the
induction of reps of 4mm from
irreps of {1,mxz}
SOLUTION
Problem 3.
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Matrices of the induced
representation for some of the
elements of 4mm
SOLUTION
Problem 3.
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LITTLE GROUP ANDLITTLE-GROUP
REPRESENTATIONS
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INDUCTION THEOREM
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ADDITIONAL
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miércoles 24 de junio de 2009