EM 2013-2014
description
Transcript of EM 2013-2014
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BFF1113Engineering MaterialsLECTURE 2
NOOR MAZNI ISMAILFACULTY OF MANUFACTURING ENGINEERING
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1. Interatomic Bonding2. Crystal Structures & Properties3. Imperfection in Solids
Bonding and Properties
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Simplified Atomic Model
• Nucleus (Proton + Neutron)
orbital electrons:
n=3 2 1
ATOM
Very small nucleuscomposed of protons& neutrons which isencircled by movingelectrons
ATOMIC MODELS
Some Terminologies (basic structure for elements)
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F19
9
Example:
Determine the number of Proton, electron and neutron in a fluorineatom.
XA
Z
AtomicMass
AtomicNumber
A = p + n = 19
Z = p = e = 9
n = A – Z = 19 – 9 = 10• Proton = 9• Electron = 9• Neutron = 10
Answer:
Atomic mass (A) ≈ Z + N• Z (atomic number) = # protons
• N = # neutrons
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The mass and charge of Proton, Neutron,and Electron
Mass (g) Charge (C)
Proton 1.673 x 10-24 +1.602 x 10-19
Neutron 1.675 x 10-24 0
Electron 9.109 x 10-28 -1.602 x 10-19
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Why we need to understand theconcept of interatomic bonding insolids?1. INTERATOMIC BONDING
Some important properties of solid depend on geometricalatomic arrangements & also the interactions that existamong constituent atoms or moleculesExample: Carbon ~ graphite & diamond
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InteratomicBonding
Primary Bonding Secondary Bonding
• Ionic bonds• Covalent bonds• Metallic bonds
• Van der Waals bonds• Hydrogen bond
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3 different types of primary or chemical bond are found in solids.Ionic, covalent, and metallic.Involve valence electronsNature of bond depends on electron structures of the constituentatoms. Tendency of atoms to assume stable electron structure.
Secondary (or physical) forces and energies also found in many solidmaterials.Wan Der Waals, Hydrogen bondWeaker than primary onesInfluence physical properties of some material
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Primary Bonding> Ionic Bonding> Covalent Bonding> Metallic Bonding1.1: Primary Interatomic Bonds
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Formed between highly electropositive (metallic) elements andhighly electronegative (nonmetallic) elements.
Ionization: electrons are transferred from atoms of electropositiveelements to atoms of electronegative elements, producingpositively charged cations and negatively charge anions.
Ionic bonding: due to electrostatic / coulombic force attractionof oppositely charged ions.
Binding energy large high melting temp.
Ionic material hard, brittle, electrically and thermally insulative.
Ionic Bonding
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• Predominant bonding in Ceramics
Give up electrons (electropositive) Acquire electrons (electronegative)
He-
Ne-
Ar-
Kr-
Xe-
Rn-
F4.0
Cl3.0
Br2.8
I2.5
At2.2
Li1.0
Na0.9
K0.8
Rb0.8
Cs0.7
Fr0.7
H2.1
Be1.5
Mg1.2
Ca1.0
Sr1.0
Ba0.9
Ra0.9
Ti1.5
Cr1.6
Fe1.8
Ni1.8
Zn1.8
As2.0
CsCl
MgO
CaF 2
NaCl
O3.5
Adapted from Fig. 2.7, Callister 6e. (Fig. 2.7 is adapted from Linus Pauling, The Nature of theChemical Bond, 3rd edition, Copyright 1939 and 1940, 3rd edition. Copyright 1960 by CornellUniversity.
EXAMPLES: IONIC BONDING
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Sodium atom, Na Chlorine atom, Cl
+ -
Sodium ion, Na+Chlorine ion, Cl-
Unstable Unstable
Stable Stable
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In covalent bonding stable electron configurations are assumed bysharing of electrons between adjacent atoms.Two atoms that are covalently bonded will each contribute at least oneelectron to the bond, and the shared electrons may be considered tobelong to both atoms.H• + H• H:H (1s1 electron from hydrogen atom)
Covalent Bonding
Many nonmetallic elemental molecules (H2, Cl2, F2, etc)Molecules containing dissimilar atoms (CH4, H2O, HNO3, HF, etc)Other elemental solids: diamond (carbon), silicon, germaniumBinding energy & melting temp for covalently bonded materials very high(diamond) to very weak (bismuth, polymeric material)Possible of having interatomic bonds (partially ionic and partially covalent).
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shared electronsfrom carbon atom
shared electronsfrom hydrogenatoms
H
H
H
H
C
CH4
• Example: CH4 (methane)
C: has 4 valence e,needs 4 more
H: has 1 valence e,needs 1 more
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• Molecules with nonmetals• Molecules with dissimilar atoms• Elemental solids (RHS of Periodic Table)• Compound solids (about column IVA) (SiC, GaAs)
He-
Ne-
Ar-
Kr-
Xe-
Rn-
F4.0
Cl3.0
Br2.8
I2.5
At2.2
Li1.0
Na0.9
K0.8
Rb0.8
Cs0.7
Fr0.7
H2.1
Be1.5
Mg1.2
Ca1.0
Sr1.0
Ba0.9
Ra0.9
Ti1.5
Cr1.6
Fe1.8
Ni1.8
Zn1.8
As2.0
SiC
C(diamond)
H2O
C2.5
H2
Cl2
F2
Si1.8
Ga1.6
GaAs
Ge1.8
O2.0
co
lum
n IV
A
Sn1.8Pb1.8
Adapted from Fig. 2.7, Callister 6e. (Fig. 2.7 isadapted from Linus Pauling, The Nature of the Chemical Bond, 3rd edition, Copyright 1939 and 1940, 3rd edition. Copyright1960 by Cornell University.
EXAMPLES: COVALENT BONDING
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Very similar to covalent bondingValence electrons
Metallic materials have 1, 2, or 3 valence electrons.not bound to any particular atom in the solid.are essentially free electrons and move (drift) through out themetal.form a sea of electron or electron cloud.
Remaining non-valence electrons and atomic nuclei ion coresGroup IA and IIA elementsAll elemental metalsHighly conductiveDuctile,Binding energy & melting temp (wide range)
Metallic Bonding
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+ + + +
+ + + +
+ + + +
+ + + +
Ion cores- nonvalence electrons andatomic nuclei
-posses a net positivecharge equal in magnitude tothe total valence electroncharge per atom.
Sea of valence electrons- The free electrons shield the positivelycharged ion chores from electrostaticforces.- This free electrons act as a “glue” to holdthe ion cores together.
Schematic illustration of metallic bonding
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Van der Waals bond or physical bondBinding energy (typical) in the order of 10 kJ/mol (0.1 eV/atom)Exist between virtually all atoms or molecules.The presence of any of the 3 primary bonding types may obscure it.The driving force for secondary bonding is the attraction of the electricdipoles contained in atoms or moleculesElectric dipoles:- separation of positive and negative portions of an atom or molecule.- coulombic attraction between +ve end of one dipole and –ve enddipole.Schematic illustration of van der Waals bonding between two dipolesSchematic illustration of van der Waals bonding between two dipoles
Atomic or molecular dipoles
+ +
1.2: Secondary BondsVan der Waals Bonds
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READS….
HYDROGEN BONDS
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Bonding Energies and Melting Temperatures for Various Substances
Bonding Type SubstanceBonding Energy Melting
Temperature(oC)kJ/mol eV/atom, ion,
molecule
IonicNaClMgO
6401000
3.35.2
8012800
CovelentSi
C (diamond)450713
4.77.4
1410>3550
Metallic
HgAlFeW
68324406849
0.73.44.28.8
-39660
15383410
Van der WaalsArCl2
7.731
0.080.32
-189-101
HydrogenNH3
H2O3551
0.360.52
-780
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2.0 Crystal Structures & Properties
• Introduction• Arrangement of atom in metallic crystal structures• Single crystal, polycrystalline materials• X-ray diffraction: determination of crystal structure
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At the end of the lecture, students will be able:1. To describe the difference in atomic/molecular structurebetween crystalline and noncrystalline materials.2. To draw unit cells for face-centered cubic (FCC), body-centered cubic (BCC), and hexagonal close-packed crystal(HCP) structures.3. To derive the relationships between unit cell edge length andatomic radius for FCC and BCC crystal structures.4. To compute the densities for metals having FCC and BCCcrystal structures given their unit cell dimensions.5. To distinguish between single crystals and polycrystallinematerials.6. To describe briefly the use of XRD to identify an element.
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Solid materials:Classified according to the regularity with whichatoms or ions are arranged with respect to oneanother.
2 types:Crystalline materialsNoncrystalline (or amorphous) materials
ARRANGEMENT OF ATOMS
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Noncrystalline vs. crystalline SiO2
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Si Oxygen
noncrystalline SiO2 crystalline SiO2
Crystalline materials...• atoms pack in periodic (or repeating),over large atomic distances (longrange order)• typical of: -metals, -many ceramics, -somepolymers
Note: There is an extremely large number ofdifferent crystal structures all having long rangeatomic order, depending how you ARRANGE andPACK it.
Noncrystalline materials...• atoms have no periodic or repeatingpacking (not systematic).• has no long range atomic order.occurs for: -complex structures, -rapid cooling
"Amorphous" = Noncrystalline
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How many types of crystal structures are available?
How many types of unit cell? (Unit cell – small repeat entities)***Smallest group of atoms showing the lattice structure is known as a unit
cell
Depends on types of lattices ( 3D array of point coinciding with atompositions)
There is an unlimited number of possible lattices because there is nonatural restriction on the lengths of lattice translation vectors or on theangle between them.
3 primary directional length + 3 angles between the 3 directions type ofunit cell a3
a2
a1
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Crystal systemRestriction on
conventional cell axesand angles
Triclinica1 a2 a3
Monoclinica1 a2 a3
= = 90o
Orthorhombica1 a2 a3
= = = 90o
Tetragonala1 = a2 a3
= = = 90o
Cubica1 = a2 = a3
= = = 90o
Trigonala1 = a2 = a3
= = < 120o, 90o
Hexagonala1 = a2 a3
= = 90o
= 120o
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• Rare due to poor packing (only Polonium has this structure)• Close-packed directions at cube edges (1 unit cell).FYI only: SIMPLE CUBIC STRUCTURE (SC)
3 basic atomic arrangements:
1. Face-centered cubic (fcc)2. Body-centered cubic (bcc)3. Hexagonal close-packed (hcp)
The Crystal Structure of Metals• have the simplest crystal structures.
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Assumptions used to describe crystal structure:
When describing crystalline structures, atoms (or ions) are
thought of as being solid spheres having well defines diameters
(2 R).
This is termed the atomic hard sphere model in which spheres
representing nearest-neighbor atoms touch one another.
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FACE CENTERED CUBIC STRUCTURE (FCC)
6 atom locateat surface(shared),8 at corners(shared).
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Equivalent number of atom
= 6 x 1/2 + 1/8 x 8
= 4 atom/unit
Unit cellHard-ball model Single crystal withmany unit cells
a = the cube edge length
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CALCULATIONS:
1)VOLUME OF CELL
2)ATOMIC PACKING FACTOR
3)DENSITY OF CELL
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Example 1:
a
a2 + a2 = (4R)2
a = 4R/√2
Volume = a3
= (4R/√2)34R
Calculate the volume of a FCC cell with atomic radius of R.
Volume = Width x Length x Height
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APF =Volume of atoms in unit cell*
Volume of unit cell
*assume hard spheres
ATOMIC PACKING FACTOR(Fraction of spaced occupied by atoms)
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a
34
APF =a3
4
3( 2a/4)34
atoms
unit cell atomvolume
unit cell
volume
Unit cell contains: 6 x 1/2 + 8 x 1/8 = 4 atoms/unit cell
• APF for a face-centered cubic structure = 0.74
Close-packed directions:length = 4R
= 2 a
ATOMIC PACKING FACTOR: FCC
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the APF of FCC = 0.74, calculated in term of the atomicradius, R:
APF = V atom/ V unit cellV atom = (4)(4/3πR3) = 16.757R3
V unit cell = a3
= (4R/√2 )3
= 22.63R 3
APF = 16.757R3 / 22.63R 3
= 0.74
Example 2:
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BODY CENTERED CUBIC STRUCTURE (BCC)
• 1 atom locateat center, 8 atcorners(shared)
Hard-ballmodel
Unitcell
Single crystalwith many unit
cells
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a 4R
a√2
a2 + (a√2)2 = (4R)2
a = 4R/√3
Volume = a3
= (4R/√3 )3
Calculate the volume of a BCC cell with atomic radius of R.
Example 2:
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aR
• APF for a body-centered cubic structure = 0.68
Close-packed directions:length = 4R
= 3 a
Unit cell contains: 1 + 8 x 1/8 = 2 atoms/unit cell
Adapted fromFig. 3.2,Callister 6e.
ATOMIC PACKING FACTOR: BCC
APF =a3
4
3( 3a/4)32
atoms
unit cell atomvolume
unit cell
volume
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Prove the APF of BCC = 0.68
APF = V atom/ V unit cellV atom = (2)(4/3πR3) = 8.373R3
V unit cell = a3
= (4R/√3 )3
= 12.32 R 3
APF = 8.373R3 / 12.32 R 3
= 0.68
Example 3:
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HEXAGONAL CLOSE-PACKED STRUCTURE (HCP)
For HCP crystal structure, (a) a reduced-sphere unit cell: a and c represent theshort and long edge lengths, respectively), and (b) an aggregate of many atom.
HCP crystals have the most densely packed configurations, followed by fcc and bcc Arrangements can be modified by adding atoms of other metals known as
alloying.
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Number of atoms in a unit of HCP cell:No. atom/unit = 612 atoms at each corner/6 unit cell = 22 atoms at top and bottom of the hexagonal/2 = 13 atoms inside the hexagonal = 3
APF = 0.74
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n AVcNA
# atoms/unit cell Atomic weight (g/mol)
Volume/unit cell
(cm3/unit cell)Avogadro's number
(6.023 x 1023 atoms/mol)
THEORETICAL DENSITY,
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Example 4: Copper
Data from Table inside front cover of Callister (see next slide):
• crystal structure = FCC: 4 atoms/unit cell• atomic weight = 63.55 g/mol (1 amu = 1 g/mol)• atomic radius R = 0.128 nm (1 nm = 10-7 cm)
Vc = a3 ; For FCC, a = 4R/ 2 ; Vc = 4.75 x 10-23cm3
Compare to actual: Cu = 8.94 g/cm3
Result: theoretical Cu = 8.89 g/cm3
Note: close agreement with the literature value given in the table
ρ = nAVcNA
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ElementAluminumArgonBariumBerylliumBoronBromineCadmiumCalciumCarbonCesiumChlorineChromiumCobaltCopperFlourineGalliumGermaniumGoldHeliumHydrogen
SymbolAlArBaBeBBrCdCaCCsClCrCoCuFGaGeAuHeH
At. Weight(amu)26.9839.95137.339.01210.8179.90112.4140.0812.011132.9135.4552.0058.9363.5519.0069.7272.59196.974.0031.008
Atomic radius(nm)0.143------0.2170.114------------0.1490.1970.0710.265------0.1250.1250.128------0.1220.1220.144------------
Density(g/cm3)2.71------3.51.852.34------8.651.552.251.87------7.198.98.94------5.905.3219.32------------
CrystalStructureFCC------BCCHCPRhomb------HCPFCCHexBCC------BCCHCPFCC------Ortho.Dia. cubicFCC------------
Characteristics of Selected Elements at 20oC
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(g
/cm
3)
Graphite/Ceramics/Semicond
Metals/Alloys
Composites/fibersPolymers
1
2
20
30Based on data in Table B1, Callister
*GFRE, CFRE, & AFRE are Glass,Carbon, & Aramid Fiber-ReinforcedEpoxy composites (values based on60% volume fraction of aligned fibers
in an epoxy matrix).10
345
0.30.40.5
Magnesium
Aluminum
Steels
Titanium
Cu,Ni
Tin, Zinc
Silver, Mo
TantalumGold, WPlatinum
GraphiteSilicon
Glass-sodaConcrete
Si nitrideDiamondAl oxide
Zirconia
HDPE, PSPP, LDPE
PC
PTFE
PETPVCSilicone
Wood
AFRE*
CFRE*
GFRE*
Glass fibers
Carbon fibers
Aramid fibers
Why?Metals have...
• close-packing
(metallic bonding)• large atomic mass
Ceramics have...• less dense packing
(covalent bonding)
• often lighter elements
Polymers have...• poor packing
(often amorphous)
• lighter elements (C,H,O)
Composites have...• intermediate values
Data from Table B1, Callister 6e.
DENSITIES OF MATERIAL CLASSES
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Single crystal and polycrystallinematerialsSingle crystal Periodic and repeated arrangementof atoms is perfect or extends throughout the entiretyof specimen without interruption.Only 1 Crystal – environment must be carefullycontrolledAll unit cells interlock in the same way & have sameorientation, geometry shape having flat surface.
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Single crystal
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• Some engineering applications require single crystals:
Semiconductor- single crystal are necessary to allow electron flow more‘easily’ w/out disturbance of grain boundaries
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• Most engineering materials are polycrystals.Composed of collection of many small crystals or grain
• Crystal sizes typ. range from 1 nm to 2 cm(i.e., from a few to millions of atomic layers).
Adapted from Fig. K,color inset pages ofCallister 6e.(Fig. K is courtesy ofPaul E. Danielson,Teledyne Wah ChangAlbany)
1 mm
POLYCRYSTALS
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Plastic Deformation of Polycrystalline Metals
• When a polycrystalline metal with uniform equiaxedgrains is subjected to plastic deformation at roomtemperature, the grains become deformed andelongated
• During plastic deformation, the grain boundariesremain intact and mass continuity is maintained
• Increase in strength depends on the degree ofdeformation (strain)
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Plastic Deformation of Polycrystalline Metals
Anisotropy (Texture)• A result of plastic deformation• Grains have elongated in one direction and contracted
in the other• Metal has become anisotropic, where properties in the
vertical direction are different from those in thehorizontal direction
• Anisotropy influences bothmechanical and physicalproperties of metals
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Plastic Deformation of Polycrystalline Metals
Preferred Orientation• Also called crystallographic anisotropy• When metal is subjected to tension, the sliding blocks
rotate toward the direction of the tensile force• Slip planes and bands tend to align themselves with the
general direction of deformationMechanical Fibering• Results from the alignment of inclusions (stringers),
impurities, and voids in the metal during deformation• Impurities will weaken the grain boundaries and
become less ductile when tested in the verticaldirection
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Recovery, Recrystallization, and Grain Growth
• Properties of the metal can be recovered by heating themetal to a specific temperature range for a given periodof time
• A process called annealing
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Recovery, Recrystallization, and Grain Growth
• 3 events take place consecutively during the heatingprocess:
1. Recovery:Occurs below recrystallization temperature, stressesin the highly deformed regions are relieved
2. Recrystallization:Within a certain temperature range, new equiaxed andstrain-free grains are formed to replace older grains
3. Grain growth:Grains begin to grow in size and exceed the originalgrain size when temperature is raised further
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X-Ray DiffractionHow we identified this ‘white powder’?
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What is X-raydiffraction?• A form of electromagneticradiation• Having high energyWhy X-ray Diffraction (XRD)?
• We can understand atomic and molecular arrangementsin solids.
• Crystal structures & type of materials.
• We can development new materials
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CLASS ACTIVITY !!
a Calculate the volume ofa BCC cell with atomicradius of R.
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ANSWER
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1. Interatomic Bonding2. Crystal Structures & Properties3. Imperfection in Solids
Bonding and Properties
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Topic ContentsIntroductionPoint Defect
Vacancies and Self-InterstitialsImpurities in SolidSpecification of Composition
Miscellaneous ImperfectionsDislocations – Linear DefectsInterfacial DefectsBulk or Volume Defects
Microscopic ExaminationGeneralMicroscope Techniques
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INTRODUCTION
• What are the solidification mechanisms?
• What types of defects arise in solids?
• Can the number and type of defects be variedand controlled?
• How do defects affect material properties?
• Are defects undesirable?
ISSUES TO ADDRESS...
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• The solidification of metal & alloy - important industrial process• Most metal are melted & then cast into semifinished or finished
shape.• Solidification- result of casting of molten material
• Nuclei form• Nuclei grow to form crystals – grain structure
• Start with a molten material – all liquid• Crystals grow until they meet each other
nuclei crystals growing grain structureliquid
Solidification
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a) Small crystallite nuclei (molten)
b) Growth of the crystallites; the obstruction (block)of some grains that are adjacent to one anotherhave formed
c) Upon completion of solidification, grains (atomicmismatch) having irregular shapes have formed
d) The grain structure as it would appear under the microscope (darklines are the grain boundary)
Stages of solidification of polycrystalline material
Unit cell
Cooling Process
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• Solidified metal containing many crystal is said to be polycrystalline.• Number and size of the grains depends on the rate at which nucleation takes
place• The crystal in the solidified metal are called grains and the surface between
them, grain boundaries.
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Grains can be - equiaxed : Crystal grow equally in all direction, roughly samesize in all directions
: Commonly found adjacent to a cold wall –highconcentration of nuclei during solidification
- columnar (elongated grains) – long, thin coarse grain whenmetal solidifies rather slowly (temperature gradient)
Grain Refiner - added to make smaller, more uniform, equiaxed grains(ex: -Scandium).
Example 1:
Heat Flow
Heat Flow
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Imperfections in Solids
Before this we assume the arrangement of atoms wereperfect.But, in reality crystals are never perfect. Imperfection/defect – affect many of their physical &
mechanical properties.
So, good or not to us?
Example:- Sterling silver (92.5% Silver, 7.5% copper (impurities)- strong & hard compared to pure silver.
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Types of Imperfections
• Vacancy atoms• Interstitial atoms• Substitutional atoms
Point defects
• Dislocations Line defects
• Grain Boundaries Interfacial / Area defects
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i. Vacancy
ii. Self-interstitial
iii. Substitutional
1.0: Point Defects
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• Vacancies:-vacant atomic sites in a structure.
i. Vacancies
Vacancydistortionof planes
The simplest of the point defect – vacancy or vacant latticesite. One normally occupied from which an atom is missing All crystalline solids contain vacancies. Vacancies can moves and exchange site with neighbors
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• Interstitials:-"extra" atoms positioned between atomic sites.
ii. Interstitials
self-interstitial
distortionof planes
An atom from crystal that is crowded into interstitial site. A small void space that under ordinary circumstances is not occupied.
Impurities atoms fill the voids or interstices among the host atoms. In metal – self-interstitial introduces relatively large distortions in the
surrounding lattice. For metallic materials with high atomic packing factors – interstitial relatively
small. Example: carbon in FCC Iron – atomic radius difference 42% but carbon can
dissolved interstitially in iron
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iii. Substitutional
Solute/impurity atom replace or substitute for the host atoms
Factors: (Hume-Rothery Rules)i. Atomic size factor – impurity atom may be accommodated of
solid solution only when the difference in atomic radii betweenthe two types less ± 15%.
ii. Crystal structure – for both atom types must be the same.iii. Electronegativity - must be the sameiv. Valences - must be the same
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A substitutional solid solution for Cu and Ni
Cu NiAtomic Radius (nm) 0.128 0.125Crystal Structure FCC FCCElectronegativity 1.9 1.8Valence +1/+2 +2
Example:
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Two outcomes if impurity (B) added to host (A):• Solid solution of B in A (i.e., random dist. of point defects)
• Solid solution of B in A plus particles of a newphase (usually for a larger amount of B)
OR
Substitutional solid soln.(e.g., Cu in Ni)
Interstitial solid soln.(e.g., C in Fe)
Second phase particle
Point Defects in Alloys
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1. Schottky Imperfectionwhen two oppositelycharged ions are missingfrom an ionic crystal, acation-anion divacancy iscreated.
2. Frenkel Imperfection
if a positive cation moves intoan interstitial site in an ioniccrystal, a cation vacancy iscreated in the normal ion site.
Ionic Crystals Point Defects
• 2D representation of an ionic crystalillustrating a Schottky defect and aFrenkel defect.
In ionic crystal defects are more complex due to the necessity to maintainelectrical neutrality.
For example: Very small amounts of subtitutional impurity atoms in pure silicon cangreatly affect its electrical conductivity for use in electrical in electronic device.
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Impurity of atoms in solidTerms:1. Solvent – the element or compound that is present in
the greater amount. Also called host atom.
2. Solute / Impurity – used to denote an element orcompound present in a minor concentration.
3. Alloy – a metallic substance that is composed of twoor more elements (maybe metal & nonmetals)
4. Solid solution – as solute atoms are added to thehost material, the crystal structure is maintained andno new structures are formed
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Linear Defects (Dislocations)• are one-dimensional defects around which atoms are misaligned• slip between crystal planes result when dislocations move• cause Lattice distortation
• Edge dislocation:• extra half-plane of atoms inserted in a crystal structure• Burger’s factor, b to dislocation line. (tee :+ve edge dislocation line)
• Screw dislocation:• spiral planar ramp resulting from shear deformation• b to dislocation line
• Mixed dislocation:• Combination of edge and screw dislocation
2.0: Linear defects – Dislocations
Schematic of Zinc (HCP):
• before deformation• after tensile elongation
slip steps
Adapted from Fig. 7.8, Callister 7e.
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Edge dislocation
Burger’s vector, b:measure of latticedistortion
Perpendicular to the edgedislocation line
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Screw Dislocation
Burgers vector b
Dislocationline
b
(a)(b)
Screw dislocation
Shear force
Shear force
Shifted one atomic distance (A-B)
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Edge, Screw, and Mixed Dislocations
Edge
Screw
MixedShear force
Shear force Screw dislocation at frontsurface gradually changeto edge dislocation at sideof crystal
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3.0: Interfacial / Area Defects:
• Grain boundary defect is a boundary that separate two smallgrains or crystals.
• Examples:
• External surfaces, grain boundaries, twinboundaries, stacking faults and phaseboundaries.
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3.0: Interfacial / Area Defects:
• regions between crystals• transition from lattice of one
region to that of the other• slightly disordered• Orientation mismatch (angle
of misalignment)• Small angle GB – less surface
energy, formed by edge &screw dislocation.
Adapted from Fig. 4.7, Callister 7e.
Microstructure in atomic perspective
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Planar Defects in Solids
• twin boundary (plane)• Essentially a reflection of atom positions across the twin plane.
• Twins result from:• atomic displacements that are produced from applied mechanical shear
forces (mechanical twins)• Also during annealing heat treatments following deformation (annealing
twins) when atom reposition themselves
• Stacking faults– For FCC metals an error in
ABCABC packing sequence– Ex: ABCABABC– Because of: vacancy cluster,
dislocation one or morestacking plane
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4.0: Bulk or Volume Defects
• Theses include pores, cracks foreign inclusion and other phases• They are normally introduced during processing and fabrication
steps.
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Microscopic Examination
• Crystallites (grains) and grain boundaries. Varyconsiderably in size. Can be quite large
• ex: Large single crystal of quartz or diamond or Si• ex: Aluminum light post or garbage can - see the
individual grains• Crystallites (grains) can be quite small (mm or less)
– necessary to observe with a microscope.
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• Useful up to 2000X magnification.• Polishing removes surface features (e.g., scratches);
surface like mirror• Etching changes reflectance, depending on crystal
orientation.
Micrograph ofbrass (a Cu-Zn alloy)
0.75mm
Optical Microscopy
Adapted from Fig. 4.13(b) and (c), Callister 7e.(Fig. 4.13(c) is courtesyof J.E. Burke, General Electric Co.
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Grain boundaries...• may be revealed as
dark lines,• change in crystal
orientation acrossboundary.
Optical Microscopy
ASTM grainsize number
N = 2 n-1
number of grains/in2
at 100xmagnification Fe-Cr alloy
(b)
grain boundarysurface groove
polished surface
(a)
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Electron Microscope
• Electron Microscope:
i. The Scanning Electron Microscope (SEM)
ii. Transmission Electron Microscopy (TEM)
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i. The Scanning Electron Microscope (SEM)
• The upper limit of optical microscope ~2000x.• but, some structural elements are too fine/small.• need higher magnification• An image of the structure under investigation is formed
using beams of electrons instead of light radiation.
• The surface of a specimen to be examined is scanned withan electron beam, and the reflected (or back-scattered)beam of electron is collected, then displayed at the samescanning rate on a cathode ray tube (similar to a CRT TVscreen)
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ii. Transmission Electron Microscopy (TEM)
• The image seen with a TEM is formed by anelectron beam that passes throughspecimen.
• Details of internal microstructural featuresare accessible to observation
• Since solid materials are highly absoptive toelectron beams, a specimen must be verythin.
• Magnification 1 000 000x are possible.
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Scales
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• Point, Line, and Area defects exist in solids.
• The number and type of defects can be variedand controlled (e.g., T controls vacancy conc.)
• Defects affect material properties (e.g., grainboundaries control crystal slip).
• Defects may be desirable or undesirable(e.g., dislocations may be good or bad, dependingon whether plastic deformation is desirable or not.)
Summary
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END OF LECTURE 2Thank you